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How a thermally sealed spa works in
relation to the standard full foam.
copyright 2000-2014 Havenmade
Most all of the information on spa insulation is incorrect when
comparing a thermal sealed spa to a fully foamed spa. It is
nothing more than sales nonsense. The concept for the
thermal sealed spa came about sometime in the early 90's. It
evolved out of several spa designs. The full foam sales people are
incorrect when they group a thermal closed design in with the
other "non full foam" designs. As soon as you see open vents,
louvers, or big holes in the bottom, you know it isn't a thermally
efficient spa.
The thermal closed cabinet design has four basic beneficial
features that make it a superior design for insulation:
energy efficiency, better filtration , quiet operation, and
the most freeze protection available.
One of the basic concepts of this design is to stop wasting energy
from the spa pump motors that is typically lost in most spas. When
any pump runs, it puts out heat exhausted and radiated from the
motors. There are three types of heat generated, radiant from the
heated induction winding wires inside the motor that heat the
frame, forced convection heat from the motor's fan,
and frictional heat generated by moving parts and the water going
through the water pipes. As one engineer put it: "All energy
ultimately is dissipated as heat". When nearly all of the motor
heat is available to the spa water, the spa becomes more
efficient, because the spa's electric water heater is not used
nearly as much.
The other part of this concept is warm air thermal barrier
created by the warm air in the cabinet.
This is designed to stop the loss of heat from the sides of the
spa vessel (the seating area). This is accomplished by using the
warm air from the spa motors as well.
In our solar heated spas, we have a heat exchanger inside the
cabinet to put actual solar water heat in the cabinet to heat the
air and keep it warm, because it stops the waste of energy from
the solar storage tank. If you heat the air the the water in
the spa vessel stays hot. The only issue then is the cover.
If you use a Havenmade custom hot air cover, it does the same
thing to complete the outer warm air chamber.
The third beneficial concept of this is actually a by product of
the energy conservation of this system. There is a much better
filtration achieved by moving more water through the filter or
filters per day at higher circulation rates. ( In solar spas we
adjust to less water flow but longer and less heat from the motor,
because the solar heat exchanger inside the cabinet it what keeps
it warm.) Because the heat from the motors is used to eliminate a
large quantity of the water heater energy, we can run the motors
and have more filtering with cleaner water. The resistive electric
heater that uses more power than any other component in the spa is
the most expensive component to operate. If we could totally
eliminate that heater, then the spa would be near perfect in
design. In Haven Spas we come very close to that
"perfection" with the DAIT
Heated air creates effective "infinite"* conduction "R Value" insulation
Here is a basic law of thermodynamics:
If one form of matter, solid, liquid, or gas, is in contact with another form of matter, the heat from one to the other is transferred by going in the direction of warmer matter to the cooler matter. Heat transfers from hot to cold is a simpler way of putting it.
For instance, if the water in the spa vessel is 102 degrees, and the shell is 100 degrees with no extra insulation, the heat is being transferred from the water through to the shell and then to the outside environment. The degree of insulation in this case is less than R1 and the heat loss is immense. If the air on the outside is 70 degrees then the 100 degree shell will transfer its heat out to the outside environment at a predictable rate.
Here is another law of energy transfer. It takes a lot less energy to warm "one gallon" of air than one gallon of water. I looked up the formula for this and it is shown below. The difference is tremendous, more than 3,500 times more energy required.
Since air weighs in at .075 pounds per cubic foot while water weighs in at 63 pounds per cubic foot. ( a box of air vs. a box of water), water weighs 840 times more than air. A simple demonstration of this is to put a bubble of air under the water and watch how fast it moves to the top. Fill a box with water and lift it. "Fill" a box of air and lift it. This means that it takes about 3500 times as much energy to heat the same amount by volume of water from 40 degrees F. to 102 degrees F as it does to heat the same volume of air.
------------------------------------------------------------------------
Here is the formula Since water is the basis of these calculations, the mass factor for water is 1 (one). The source of this information comes from http://www.watlow.com a manufacturer of heater equipment.
Equation 1
Heat Required To Raise The Temperature of A Material
Where:
Q1 = Heat required to raise temperature
W = Pounds of material
CP = Specific heat of material (Btu/lb-ºF)
(Delta)T = Temperature rise of material (TFinal - TInitial) ºF
Water:
There are 3412 Btu's per kilowatt hour of electricity. So how many kilowatts does it take to heat one cubic foot of water from 70 degrees to 102 degrees; a 32 degree differential?
63 (the mass of water) X 1 ( base factor ) X (102 - 70) / 3412 = .591 KWH
It takes 0.591 kilowatt hours (591 Watt Hours) to raise one cubic foot of water 30 degrees. ( For reference that is equivalent to about 6 each, 100 watt, light bulbs burning for one hour.)
Air:
.075 (the mass of air at 70 degrees F.) X .240 ( base factor ) X (102 - 70) / 3412 = .0001688 KWH (I don't know of a light bulb that uses 0.16 watt hours. It is a very small amount of energy.)
So it takes .591 / .0001688 =
3,501 times more energy to heat the same volume of water. Or
water is 3,501 more energy harder to heat than air. This is
something that is primary to understanding how a thermally closed
spa insulates. (It also shows us exactly how foam, like
Styrofoam, insulates as well.)
Air heats up almost instantaneously. Water takes much longer.
Water is often used as storage for solar energy in tanks because
of this.
-------------------------------------------------------------------
So air is a lot less dense than water and costs a lot less (minuscule energy) to heat the same volume of air than water.
Picture a container split it into two halves by a thin membrane of near zero R value plastic with infinite insulation all around. This is like taking a jar and dividing it in half, putting air in one side and warm water in the other side. As soon as the air reaches the water temperature, the heat transfer stops from the water to the air.
In other words; when the air reaches the water temperature, or is warmed to the water temperature, the heat transfer out of the water is stopped dead in its tracks.
This is the big "secret" of a thermal closed cabinet with the
motors inside the closed cabinet. You could have zero insulation
on the outer wall of the spa, and put all the insulation on the
outer cabinet, and we do that pretty much on our spas, since the
lightweight foam is mostly to hold the plumbing pipes from
vibrating. (On our European models we are using a tying
method to hold them.)
As the motors run, they heat the air chamber inside the spa
contained between the shell and the outer insulated wall in a
thermal sealed cabinet designed spa. When the air inside the
chamber becomes warm as the water, there is an " R infinite"
insulation created. All of the heat loss on the outside of the
shell is stopped completely as soon as the air is the same
temperature as the water. Because it costs so much less (3143
times less) to heat the air, we are using a very economical heat
retainer, warm air. As the pumps run inside the cabinet, ( doing a
great job of filtering ) the warm air is created, when the pumps
stop, the air cools down, but never as cool as the outside
air. Then the spa water will actually heat the air and
create its own insulation.
So the common arrangement of this design is a closed cabinet with
about 2 to three inches of foam, or no foam, on the shell and one
inch foam boards in the outer wall of the spa, then the wood or
plastic skirt. There are no venting holes purposely placed in the
cabinet.This works better than any full foam spa ever made.
There is a much higher insulation on the Haven Spas outer cabinet,
but even with a no foam boards and no insulation other than the
wood that covers the cabinet (like the early Cal Coop spas), have
better insulation than the full foam spas. This is proven fact in
data that I collected. It is the thermal seal that does the
main work. If you do nothing else but seal the cabinet as
tight as you can, you are better off than a full foam spa with
vented cabinet.
This design can become too heat retentive by not allowing the spa to cool between filter cycles. Because we are literally putting all the heat possible into the spa water, we must not overdo it . It just so happens that the only time the jet pumps are on high at the peak of thermal efficiency, the cover is off, losing the most heat out the top. You would not want to run the jets on high while the cover was on, this never happens under normal use. Why would anyone run the jets on high with the cover on, unless it was for a thermal test? Don't run a Haven Spa in summer with the cover on unless you are trying to raise the water above the temperature setting.
The biggest concern with this design is that it does not
become too heat retentive in the summer. It is recommended to not
run the filtering during the heat of the day, but to filter at
night and early morning. This gives us the optimum energy
efficiency (for any season), and clean water with out the use of
ridiculous 7 to 3 GPM tiny circ pumps. With Havenmade solar
hot tubs the mechanical (not powered) thermostat is
used inside the cabinet to control the air
temperature. This solves the problem of overheat caused by
filtering. Using a reduced size but continuous DC powered
circulation pump maintains the water filtering.
As the air in the cabinet, heated by the pump, gets above the
temperature of the water, the motor heat will start to transfer
into the water. It is drawn in by the air controls, the exposed
equipment, exposed pipes, and through the wall of the spa and
through the air pump. Now even though the air is less dense, about
840 times less dense, we are taking the heat from a confined
machine, an electric motor of about 0.23 cubic feet, the heat is
dissipated into a volume of 16 cubic feet or more. So it is
16/0.23 ratio for heat dissipation. 69 time the volume. As the
temperature rises to, say, 10 degrees above the water temperature,
the heat is transferred much more quickly. The point is that we
don't waste the motor heat.
Another rule about heat transfer, is the greater the difference between two masses in temperature the faster the heat is transferred. The barrier of heat resistance between the two masses has a predictable effect on the heat transfer.
For instance, which has more heat loss, a spa shell with 2 of inch foam with 102 degree water inside and 0 degrees F outside the foam, or the same with 102 inside and 70 degrees outside?
I think the answer is obvious. The higher the temperature differential, the faster the heat transfer. If you never have a great temperature difference, then the heat loss is minimized.
Inside a thermal pane or thermal sealed cabinet, the residual
heat from the water actually helps to insulate itself. The water
heat in the vessel will begin to warm the air in the chamber when
the pumps are turned off. This keeps the temp inside the spa above
70 degrees, even at sub zero weather outside. If we could
make a spa that we could raise the temperature above 104 for the
times the spa is not used, it would actually help to create a
warmer air chamber and used as a sort of solar water heat
battery, much like the solar tanks where water is often way above
140 degrees.
Equation 4
Heat Losses By Conduction Through Materials
Where:
Q4 = Conduction heat losses
K = Thermal Conductivity (Btu · in/ft2 · ºF · hour)
A = Heat transfer surface area (ft2)
X = Thickness of material (inches)
(Delta)T = Temperature difference across material (T2 - T1)ºF
t = Conduction time (hours)
In a full foam spa with say 6 inches of foam at the top, and four inches in front near the door, 12 inches at the bottom, the overall insulation value is less than a total of three inches of foam plus the wood in the cabinet in a thermal sealed spa. So full foam is actually less insulation than 3 inches of foam, dead air, and wood in a thermally closed cabinet.
8 inches of polyurethane foam is about R 48. Two inches ( or six
inches or fifty inches....so on ) of foam with warm air outside
the vessel and inside the cabinet is about
R-100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000
and
so
on.
As far as the water vessel is concerned the conduction heat loss
is gone from the sides.
*In engineering the term "infinite R-Value" conduction does not
exist except in a pure vacuum. In this demonstration we use
the term "infinite" as an illustrative word, because it is as
close of an exact word in terms of the actual effects of this
system. The heat loss out side the cabinet is zero, making
the effective R-value immeasurable and beyond the limits of all
numbers associated with the ability to stop heat transfer.
In a dynamic insulation system you cannot measure any heat loss
because there is none. We use energy to make warm air, so that has
to be put in the equation, but that energy is created by filtering
and in solar spas by the heat "radiator" from the solar water heat
stored in the tank. Yes it takes energy to make warm air so it
does use energy, but about 1/3 the cost of the highest R value
full foam spa.
Which is better, six inches of foam, or two with warm air on the outside?
In the equation above, the delta "T" (T2 - T1) degrees F. is zero
for a zero difference from the inside to the outside. If you
multiply by "ZERO", the whole heat loss is "ZERO".
In a fully foamed spa the pipes near the outside of the cabinet
wall are extremely poorly insulated. The main plumbing lines
are where this area exists. There is a fixed R-value of foam
between the pipes and the outer cabinet and that is close to 1
inch in many places, especially where the diverter valves
are. In a thermally sealed spa the 1 inch of air is still
warmer than the water and so the thickness of the "air insulation"
has no relevance.
So, as long as the cabinet temperature is as warm or warmer than
water, we have an extremely good insulation scenario. If you
filter for eight hours per day, the spa has the equivalent of
"infinite" conduction insulation for about eight hours per day. In
the winter, if it is super cold outside, the more you filter, the
less it costs to operate filtration. In the summer the spa use is
normally less, so the filtering can be reduced as necessary. ( I
call this the "Gestalt" or overall integration of all the parts of
this system. Each of the engineering principles or parts in this
system integrate with each other part extremely well.)
The heat loss when the pump is off in a thermal closed spa.
Here is another area where the laws of thermal dynamics work in
the favor of the thermally closed cabinet. The temperature
differential in the above equation, showing heat loss through
materials, works in the favor of the thermal pane or closed
cabinet design.
The water at 102 and the wall of the spa with average of 3 inches
of polyurethane foam has an R value of about 18. But the
temperature differential between the filter times ( when the pump
is off ) is less than 15 degrees average, the extremes high
temperature being 115 F degrees, and lowest of 70 F degrees.
The heat loss is strongly affected by the "DELTA T" in the equation. If it is an average of 15 degrees, then we are not dealing with more than double that in a full foam spa. In other words the 3 inches of foam in a thermal sealed spa is equal to 6 inches in a full foam (R 36) with cool air on the outside. The average temperature in most places is about 68 degrees, or 34 degrees cooler than the water.
So, for six to eight hours per day, we have infinite insulation, and the rest of the time we have an equivalent of R 36 or more by using an actual R - 24.
Here is the formula for a thermal closed spa, using the KWH ( kilowatt hours) equation 4 above;
Where:
K = .228 for polyurethane foam.
K = .18 for air ( second equation)
A = 1 square foot
X = 3 inches on the foam. ( average of 10 inches Air space).
Delta T = 15 degrees average.
t = 16 hours with the pump off during the day.
.228 X 1 x 15 x 16 / 3412 X 3 = .005345838: kilowatt hour loss in 16 hours per square foot of surface. The rest of the time there is no loss at all.
Now, we have a heat loss formula we can convert to any size of spa. 70 Square feet would be a good size spa. This is the inside square footage of water contact surface. 70 x .0053458 = .374 Kilowatt hours out the sides of the spa in 16 hours. Not much, considering that an average KWH is about 12 Cents per KWH across the country. That is 4.5 cents per day , 1.35 per month, loss from the sides. (Now the top is another story.)
What we are trying to do more than anything with a thermal closed
spa is have really clean water and have a low electric bill.
Again, with solar heated cabinet this equation never is used,
because there is no time when the inside air is not over 104
degrees.
Here's another scenario. In a typical fully foamed spa, the pipes, heater, pump housings, all have square footage of heat loss as long as the temperature of the air inside the cabinet is cooler than the spa water. There is no foam insulation on the equipment or pipes in the equipment area, and cool air is allowed into the cabinet. This is nearly all the time in winter, and most of the time in summer. Plus the spas on all the sides will never have zero heat loss, because the temperature outside the spa foam is always cooler than the spa water, almost all the time. Even when it is 90 degrees outside, the spa is still losing heat if the water is 91 or above. In a full foam spa the only time there is 100% insulation is when the water is the same temperature as the outside. Since nobody runs the temperature up and down, there is almost always heat loss.
Since the average thickness of the insulation is about 6 inches on an average full foam spa, top bottom and sides. There may be 12 inches on a diagonal from the seat to the outside, and two inches on the wall between the equipment and the outside three inches in the upper shell. That averages at R 36. The companies often brag about 30 inches of foam, but that is measured diagonally in the largest area of the spa. The type of foam is also part of the equation. An open cell foam with low density is a poor insulator. Many of the spa companies, including one of the largest, uses this type of foam. It's R-value is less than R-2 per inch in some foams.
When the "tiny circ" 24 hour pump is running in the cabinet
,which is cooler than the spa water, there is heat loss in all
those surface areas. It is a "cooler" representing about 20% or
more of the spa's total cubic feet of volume. I call it the
"cooler". When I was a child they had these things called
"coolers" in houses. It was a open backed cabinet in the kitchen.
On the back was the outside world. It kept things cooler as long
as the outside was cool. In winter the vegetables were moved to
the cellar, because they would freeze in the cooler, just like spa
equipment does. When the water inside the equipment freezes, it
expands and breaks the equipment, one of the most expensive
repairs there is.
In Havenmade Solar heated spas we use a very efficient DC
circulation pump that easily fulfills the ANSI standards for
turnover rate of filtering.
When you figure mathematically the total non insulated, water
containing parts, the average "Delta T" and the time involved, the
equipment in the front of the spa is similar to a radiator,
constantly loosing heat. While the spa's heater is on the
air in the equipment area is also cooling the water at the same
time. This is similar to placing your home heater and
sitting it on the open non heated porch.
------------------------
The "air" as insulation:
According to the data from the heater manufacturer, air has a heat transfer factor of .18, while polyurethane insulation has a heat transfer factor of .223. The lower number is better.
So, if we figure in the above equation, the air insulation in the spa between the outer skirt and the foam on the wall of the shell, we come up with this formula:
Average "thickness" of the air is about 10 inches in a large thermal closed spa, six in an average spa.
Figuring
K = .228 for polyurethane foam.
K = .18 for air ( second equation)
A = 1 square foot
X = 3 inches on the foam. ( average of 10 inches Air space).
Delta T = 15 degrees average.
t = 16 hours with the pump off during the day.
The Second Equation for heat transfer through air.
.18 ( heat loss factor for air) X 1 x 15 x 16 / 3412 X 6 = .0021101 (kilowatt loss in 16 hours per square foot of surface.)
In 16 hours that is a total loss of .0337616 kilowatt hours or $.00405 per day 12.15cents per month. With an average temp of 15 from the foam on the spa to the foam on the wall. We are now down to 72 degrees at the inside of the outer wall.
From the outer wall to the outside is a delta T of three degrees
average. The insulation R value of the outer wall is R-6 + R 4 for
the wood. R-10.
One of the most important issues in heat loss is that heat from a
spa vessel will be lost faster out the top of the vessel than from
the sides or bottom. Heat rises by convection, so the top needs
the most insulation. This is why we always tell people to get a
thermal blanket. It is one of the smartest things we sell. It
should be on the spa, winter, spring, summer, or fall, because it
also captures the ozone, making the spa a great contact chamber
for the ozone. http://www.spaspecialist.com/cover.html
I will be publishing the data on heat loss on an open spa in one
of the next articles.
We now have a special cover that uses multiple layers of
"space age" thermal foil to give us an inner warm air barrier that
we heat from the solar water and this creates the same warm air
barrier as in the cabinet.
There are a couple of notes here.
This illustration is very conservative. One standard spas pumps will come on at some time between the filtering, especially in winter. The controls we use are set up to operate on a plus and minus 1 degree range. The heater runs until the water temp is one degree above the setting and it will come back on at one degree below the setting. Since the sensor is also inside the water vessel, it minimizes the number of pump starts to heat between the filter cycles. When the pump comes on, the air inside the cabinet is warmed and the insulation becomes infinite again until the air drops below the water temperature, then the delta T in the formula starts working again. The point is, the temperature is never at 80 degrees for any long period of time, and it is normally above 80 degrees, making the "delta T" not much and the heat loss a lot less. Because the pump comes on to run when the spa calls for heat in the dead of winter, the warm air is created quickly to stop heat loss. Remember, it is a lot cheaper to heat air than water.
By breaking it up into a sort of average temperature difference,
it gives us something to calculate. Even with this conservative
calculation, we are talking about less than $1.50 per month heat
loss out the sides of the spa. Now do you understand why I say
full foam is wasting heat? If you do not understand now read
the next articles. Most of the heat loss in any spa is out the
top!!!!
I get this question from time to time. "Isn't there some
heat loss by the fact that the air on the outside of the spa is
causing a heat transfer to the outside world and what about the
convection inside the cabinet? Here are some of the factors
that make this heat loss non linear. If you place a sensor
near the spa vessel, average 102, the air is nearly the same
temperature as the water. If you place a sensor in the
middle of the thermal cabinet it is cooler, average 95 degrees.
If you place a temperature sensor on the outer wall it is
normally about 85 degrees. You may have noticed that I used
the lowest average temperature in the cabinet as an average in the
above formula. This is to account for the fact that there is
convection inside the cabinet. In a closed box the warm air
will rise and the cool will fall, as is commonly known.
Since this is a totally unpredictable part of this, the
above formula accounts for the lowest average temperature in the
cabinet. The outer wall area has measured as high as 115
degrees and the lowest 68 degrees in a large thermally closed
spa. If all of the air is heated to above 104 degrees using
solar heat, convection has no factor in this equation.
In the DAIT insulated spa the foam on the shell is less and the
foam on the outer wall is much thicker. This helps to keep
the temperature inside the cabinet much warmer and makes the
"Delta T" much less.
One of the things that most engineers seem to forget in this
formula is the effect of warming the air and slowing the heat loss
on the outside of the cabinet.
*In engineering the term "infinite R-Value" does not exist. In this demonstration we use the term "infinite" as an illustrative word, because it is as close of an exact word in terms of the actual effects of this system. The heat loss out side the cabinet is zero, making the effective R-value immeasurable and beyond the limits of all numbers associated with the ability to stop heat transfer.
Next article. Heat loss in the equipment and plumbing areas of Fully Foamed spas.
Home |
Back
to
Spa Tips Index |
Order
Book "How Spas Are Made" New Version in PDF for download. |
Order
Supplies On Line |
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Spa Buyer's
Questions and Answers |